>>90501988I apologize for the mistake in my previous response. The %b format specifier is not supported in Emacs Lisp.
One way to convert an integer to a binary string in ELisp is to use a recursive function that repeatedly divides the number by 2 and appends the remainder to a string. Here's an example of how you can do this:
(defun int-to-binary (n)
"Convert integer N to a binary string."
(if (= n 0)
"0"
(concat (if (= (mod n 2) 0) "0" "1")
(int-to-binary (floor n 2)))))
(int-to-binary 10)
;; => "1010"
Alternatively, you can use the logand function to extract individual bits from the number, as I mentioned in my previous response. Here's an example of how you can do this:
(defun int-to-binary (n)
"Convert integer N to a binary string."
(if (= n 0)
"0"
(concat (if (= (logand n 1) 0) "0" "1")
(int-to-binary (lsh n -1)))))
(int-to-binary 10)
;; => "1010"
This function uses the lsh function to shift the value of n to the right by 1 bit on each recursive call, and the logand function to test the LSB. When the value of n becomes 0, the function returns the binary string.